Page 8 - Ans Sub

Solution:
A line through point C is drawn and name it as FG where FG || AE

We know that CG || BE and CE is a transversal
From the figure we know that ∠GCE and ∠CEA are alternate angles
So, we get
0
∠GCE = ∠CEA = 20
It can also be written as
∠DCG = ∠DCE - ∠GCE
By substituting the values, we get
0
0
∠DCG = 130 - 20
By subtraction we get
0
∠DCG = 110
We also know that AB || CD and FG is a transversal
From the figure we know that ∠BFC and ∠DCG are corresponding angles
So we get
0
∠BFC = ∠DCG = 110
We know that FG || AE and AF is a transversal
From the figure we know that ∠BFG and ∠FAE are corresponding angles
So we get
0
∠BFG = ∠FAE = 110
0
∠FAE = x = 110
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