Page 7 - Ans Sub

9. AB || CD. Find the value of ‘x’.

Solution:
A line is drawn at point E which is parallel to CD and name it as EG.

It is given that EG || CD and ED is a transversal.
From the figure we know that ∠GED and ∠EDC are alternate interior angles
So, we get
0
∠GED = ∠EDC = 65
EG || CD and AB || CD
So, we get EG || AB and EB is a transversal
From the figure we know that ∠BEG and ∠ABE are alternate interior angles
So, we get
0
∠BEG = ∠ABE = 35
0
∠DEB = x
From the figure we can write ∠DEB as
∠DEB = ∠BEG + ∠GED
By substituting the values
0
0
0
x = 35 + 65
By addition
0
xo = 100
Therefore, the value of x is 100.

10. In the given figure, AB || CD. Find the value of x.

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