Page 13 - Ans Sub
P. 13

∠ABL = ∠LBC and ∠MCB = ∠MCD
                     ⇒∠ABL = ∠MCD …(2) [By (1)]
                     Adding (1) and (2), we get
                     ∠LBC + ∠ABL = ∠MCB + ∠MCD
                     ⇒∠ABC = ∠BCD
                     i.e., a pair of alternate interior angles are equal.
                     ∴ AB || CD.































































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