∠ABL = ∠LBC and ∠MCB = ∠MCD ⇒∠ABL = ∠MCD …(2) [By (1)] Adding (1) and (2), we get ∠LBC + ∠ABL = ∠MCB + ∠MCD ⇒∠ABC = ∠BCD i.e., a pair of alternate interior angles are equal. ∴ AB || CD. 13