Page 10 - NCERT Books
P. 10

98   MATHEMATICS


                              Can you find more such triplets?
                                                                                   2
                                                                                                   2
                                                                             2
                                                                                              2
                                                                                        2
                                 For any natural number m > 1, we have (2m)  + (m  – 1)  = (m  + 1) . So, 2m,
                                          2
                                2
                              m  – 1 and m  + 1 forms a Pythagorean triplet.
                              Try to find some more Pythagorean triplets using this form.
                              Example 2: Write a Pythagorean triplet whose smallest member is 8.
                                                                                                 2
                                                                                                       2
                              Solution: We can get Pythagorean triplets by using general form 2m, m  – 1, m  + 1.
                                                               2
                              Let us first take              m  – 1 = 8
                                                                   2
                              So,                                m  = 8 + 1 = 9
                              which gives                         m = 3
                                                                                 2
                              Therefore,                        2m = 6   and    m  + 1 = 10
                              The triplet is thus 6, 8, 10.  But 8 is not the smallest member of this.
                              So, let us try                    2m = 8
                              then                                m = 4
                              We get                         m  – 1 = 16 – 1 = 15
                                                               2
                                                               2
                              and                            m  + 1 = 16 + 1 = 17
                              The triplet is 8, 15, 17 with 8 as the smallest member.

                              Example 3: Find a Pythagorean triplet in which one member is 12.

                                                               2
                              Solution: If we take           m  – 1 = 12
                              Then,                              m  = 12 + 1 = 13
                                                                   2
                              Then the value of m will not be an integer.
                                                2
                                                                  2
                              So, we try to take m  + 1 = 12. Again m  = 11 will not give an integer value for m.
                              So, let us take                   2m = 12
                              then                                m = 6
                              Thus,                  m  – 1 = 36 – 1 = 35    and m  + 1 = 36 + 1 = 37
                                                                                  2
                                                      2
                              Therefore, the required triplet is 12, 35, 37.
                              Note: All Pythagorean triplets may not be obtained using this form. For example another
                              triplet 5, 12, 13 also has 12 as a member.


                                             EXERCISE 6.2
                               1. Find the square of the following numbers.
                                    (i) 32             (ii) 35             (iii) 86            (iv) 93
                                   (v) 71              (vi) 46
                               2. Write a Pythagorean triplet whose one member is.
                                    (i) 6              (ii) 14             (iii) 16            (iv) 18

                              6.5    Square Roots
                              Study the following situations.
                                                            2
                               (a) Area of a square is 144 cm . What could be the side of the square?
   5   6   7   8   9   10   11   12   13   14   15