Page 10 - LESSON NOTES
P. 10

Examples
                                                                 2
                                                                      2
                      1.  Find the centre and radius of the circle x + y − 4x − 8y − 45 = 0.
                                                                             2
                                                                2
                         Soln : The equation can be written as (x − 4x) + (y − 8y) = 45
                                               2
                                                                2
                                          ⇒ (x − 4x + 4) + (y − 8y + 16) = 45 + 4 + 16
                                                                           2
                                                               2
                                                     ⇒ (x − 2) + (y − 4) = 65
                         Therefore the given circle has centre at (2,4) and radius √65
                      2.  Find the equation of circle which passes through the point (2, −2) and (3,4) and
                         whose centre lies on the line x + y = 2.
                                                                  2
                                                                             2
                                                                                   2
                         Soln : Let the equation of circle is  (x − h) + (y − k) = r
                                    Since the circle passes through (2, −2) and (3,4) we have
                                                     2
                                                                       2
                                                                  2
                                             (2 − h) + (−2 − k) = r … … … … … … (1)
                                                   2
                                                               2
                                                                    2
                                            (3 − h) + (4 − k) = r … …… … … … … … (2)
                         Also since the centre lies on the line x + y = 2 we have h + k = 2 … … . . (3)
                         Solving the equations (1),(2) and (3) we get
                                                2
                             h = 0.7 , k = 1.3 and r = 12.58
                         Hence the equation of circle is
                                                            2
                                                                         2
                                                   (x − 0.7) + (y − 1.3) = 12.58
                      3.  Find the equation of circle with centre at (2,2) and passes through the point (4,5).
                         Soln : Equation of circle with centre at (2,2) is
                                                                         2
                                                              2
                                                                               2
                                                       (x − 2) + (y − 2) = r
                                         Since the circle passes through the point (4,5)

                                                              2
                                                                          2
                                                                               2
                                                       (4 − 2) + (5 − 2) = r
                                                                  2
                                                              ⇒ r = 13
                         Therefore equation of circle is
                                                                         2
                                                              2
                                                      (x − 2) + (y − 2) = 13
                                                        2
                                                             2
                                                                           ⇒x + y − 4x − 4y − 5 = 0
                      4.  Find the coordinates of the focus, axis, the equation of the directrix and latus rectum
                                          2
                         of the parabola y = 8x.
                                                            2
                         Soln : The given equation involves y , so the axis of symmetry is along the x-axis.
                         The coefficient of x is positive so the parabola opens to the right.
                                                             2
                         Comparing with the given equation y = 4ax, we find that a = 2.
                                 Thus, the focus of the parabola is (2, 0) and the equation of  the  directrix  of  the

                                  parabola  is x = – 2.

                                               Length of the latus rectum is 4a = 4 × 2 = 8.
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