Page 9 - LN

0 - 10 10

10 - 20 P
20 - 30 25
30 - 40 30

40 -50 Q
50 - 60 10
Total 100

Solution:

p + q = 100 - (10 + 25 + 30 + 10)
= 25
Also, Median = 33 (given)
Therefore, substituting in the formula given below, we have

Median =
where,
= lower limit of the median class.
N = total frequency.
c.f = cumulative frequency preceding the median class.
f = frequency corresponding to the median class.
h = class size of the median class.

i.e.

9