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P. 10

Since, p + q =25

               Example-6: During the medical check-up of 35 students of a class, their weights
               were recorded as follows:-

                   Weight (in kg)         Number of Students
                    Less than 38                     0
                    Less than 40                     3
                    Less than 42                     5
                    Less than 44                     9
                    Less than 46                    14
                    Less than 48                    28
                    Less than 50                    32
                    Less than 52                    35
               Draw a grouped frequency distribution table for the following and find its median.


               Solution: We first need to convert the cumulative frequency distribution table to the
               frequency distribution table as shown below:


                     Class       Frequency          Cumulative
                   Intervals                         Frequency
                    36 - 38           0                   0
                    38 - 40           3                   3

                    40 - 42           2                   5
                    42 - 44           4                   9

                    44 - 46           5                  14
                    46 - 48           14                 28
                    48 - 50           4                  32
                    50 - 52           3                  35

               Here N = 35


               The cumulative frequency just greater than 17.5 is 28 and the corresponding class is 46
               - 48.
               Thus, the median class is 46 - 48
               Therefore,   = 46, h = 2, f = 14,   cf = 14




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