Page 7 - Lesson note 5 Angle subtended by arc Ch.- 10 Circle
P. 7

170⁰ = 2 BAC
                     0
                              0
         BAC = 170 /2 = 85
        Question 4: If O is the centre of the circle, find the value of x in each of the following
        figures.














        .
         AOC = 135⁰ (Given)
        From figure,  AOC +  BOC = 180⁰    [Linear pair of angles]
        135⁰ + BOC = 180⁰
        or     BOC=   180⁰−135⁰
        or    BOC=45⁰
                                                                             As The angle subtended by an arc at the centre is double the angle
                                                                                 Subtended by it at any point on the remaining part of the circle.)
         BOC = 2 CPB
        45⁰ = 2x
                 0
          x = 45 /2
               )
         =        0


        (II)
















        Solution:
         ABC=40⁰     (given)
         ACB = 90⁰   [Angle in semicircle]
        In ΔABC,
         CAB+ ACB+ ABC=180⁰ [angle sum property]
         CAB+90⁰+40⁰=180⁰
         CAB=180⁰−90⁰−40⁰
         CAB=50⁰
        Now,  CDB =  CAB   [Angle is on same segment]
                  0
           x = 50
        (iii)
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