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Example 1:

                     Solve the equation 2y + 4 = y– 3, and represent the solution on
                     (i) the number lines,
                     (ii) the cartesian plane

               Sol We solve
               .     2y + 1 = y– 3, to get
                     2y + 1 = y– 3
                     2y–y = –3 – 1
                     i.ey = –4
                     (i).









                     (ii) We know that y = –4 can be written as 0 .x + 1 .y = –4, which is a linear
                     equation in the variables x and y.

                     Therefore, y must satisfies the equation y = –4














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