Page 3 - ws1ans

9) In the given figure, ABCD is a parallelogram. 3
(2+1+1)

(i) Prove that  ABC ≅  CDA.
(ii)Which angle is equal to DAC?
(iii)Is  ABC ≅  ACD?
Solution:
(i) (Hint: AD = BC, CD = AB, AC= AC) , SSS CRITERIA
(ii) <DAC = <BCA
(iii) NO

10) In the following figure, CD and BE are the perpendiculars drawn on AB 4
and AC, respectively such that, CD = BE. Prove that  CDB ≅  BEC, (2+2)
Is ∠ECB = ∠DBC?

Solution:
In  CDB &  BEC
(Hint: CD = BE-hypotenuse ,use RHS congruency criterion)
Yes , ∠ECB = ∠DBC (c.p.c.t)