Page 18 - N.C.E.R.T PDF INTEGERS cl 7
P. 18

18        MATHEMATICS


                                Can we say that the distributivity of multiplication over addition is true for integers
                            also? Yes.
                            In general, for any integers a, b and c,
                                                        a × (b + c) = a × b + a × c


                                Take atleast five different values for each of a, b and c and verify the above Distributive
                            property.

                  TRY THESE

                              (i) Is 10 × [(6 + (–2)] = 10 × 6 + 10 × (–2)?

                              (ii) Is (–15) × [(–7) + (–1)] = (–15) × (–7) + (–15) × (–1)?

                            Now consider the following:
                            Can we say 4 × (3 – 8) = 4 × 3 – 4 × 8?
                            Let us check:
                                  4 × (3 – 8) = 4 × (–5) = –20
                                  4 × 3 – 4 × 8 = 12  – 32 = –20
                            So, 4 × (3 – 8) = 4 × 3 – 4 × 8.
                            Look at the following:

                                  ( –5) × [( – 4)  – ( – 6)] = ( –5) × 2 =  –10
                                  [( –5) × ( – 4)]  – [ ( –5) × ( – 6)]  = 20  – 30 =  –10
                            So, ( –5) × [( – 4)  – ( – 6)] = [( –5) × ( – 4)]  – [ ( –5) × ( – 6)]
                            Check this for ( –9) × [ 10  – ( –3)] and [( –9) × 10 ]  – [ ( –9) × ( –3)]
                            You will find that these are also equal.
                            In general, for any three integers a, b and c,

                                                        a × (b – c) = a × b – a × c

                            Take atleast five different values for each of a, b and c and verify this property.


                  TRY THESE

                              (i) Is 10 × (6 – (–2)] = 10 × 6 – 10 × (–2)?
                              (ii)  Is (–15) × [(–7) – (–1)] = (–15) × (–7) – (–15) × (–1)?

                            1.5.7  Making Multiplication Easier

                            Consider the following:
                              (i) We can find (–25) × 37 × 4 as
                                  [(–25) × 37] × 4 = (– 925)× 4 = –3700
   13   14   15   16   17   18   19   20   21   22   23