Page 2 - Home assignment-correlation analysis.
P. 2

Physics: 35, 23, 47, 17, 10, 43, 9, 6, 28


                      Mathematics: 30, 33, 45, 23, 8, 49, 12, 4, 31
                              Compute the student’s ranks in the two subjects and compute the
                              Spearman rank correlation.


               Solution:-  Calculation of Spearman’s rank coefficient of correlation.

                              Let the marks scored by the students be X and mathematics be Y.


                                                                                          2
                    X            Y                                     =    −             
                                                                                 
                                                                            
                                                              
                                                 
                    35          30            3            5              -2             4
                    23          33            5            3              2              4
                    47          45            1            2             -1              1

                    17          23            6            6              0              0


                    10          08            7            8             -1              1

                    43          49            2            1              1              1

                    09          12            8            7              1              1

                    06          04            9            9              0              0

                    28          31            4            4              0              0

                                                                                         2
                   n=9                                                                     =12
                                                               6×     2
                                                      = 1 −        −  
                                                       
                                                                 3
                                                                  6×12
                                                       = 1 −      9 −9
                                                           
                                                                    3
                                                                   72          1
                                                       = 1 −          = 1 −      = 0.9
                                                           
                                                                  720         10
                       There exists a very high degree of positive correlation between marks
                       scored by the students in physics and mathematics.

                       In case of equal ranks, we apply the formula: -


                                                    3        −   2     −   3
                                                            3
                                                                    3
                                                     −   1
                                                2
                                         6×(     +  1    +  2    +  3    +⋯………….).
                                                            12
                                 = 1 −               12        −    12
                                  
                                                             3
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