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Example:

               In a parallelogram ABCD, two point P and Q are taken on its diagonal BD such that DP =
               BQ. Prove that APCQ is a parallelogram.













               Given: P and Q are two points on diagonal BD such that DP = BQ.

               To prove: APCQ is a parallelogram.
               In triangles APD and CQB, we have,
               DP = BQ      (given)
               AD = BC    (opposite sides of parallelogram ABCD)
               and    ADP =     CBQ      (alternate angles when BD intersects parallel lines AD and BC)
               Therefore,    APD      CQB         (by SAS criterion of congruency)
               Therefore, AP = CQ      (by cpct)
               Similarly, taking triangles CPD and AQB, we can prove that
               CP = AQ
               Therefore, APCQ is a parallelogram.    (by the property 5 i.e. if the opposite sides are equal,
               then it is a parallelogram)







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