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12. AP and BQ are the bisectors of the two alternate interior angles formed by the 3
intersection of a transversal ‘t’ with parallel lines l and m (in the given figure).
Show that AP || BQ.

Solution:

Given In the figure l || m, AP and BQ are the bisectors of ∠EAB and ∠ABH,
respectively.
To prove: AP|| BQ
Proof :Since, l || m and t is transversal.
Therefore, ∠EAB = ∠ABH [alternate interior angles]

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