Page 20 - pdf N.C.E.R.T INTEGERS CH 1

20 MATHEMATICS

[(–30) × 13] + [(–30) × (–3)] = –390 + 90 = –300

So, (–30) × [13 + (–3)] = [(–30) × 13] + [(–30) × (–3)]
EXAMPLE 4 In a class test containing 15 questions, 4 marks are given for every
correct answer and (–2) marks are given for every incorrect answer.
(i) Gurpreet attempts all questions but only 9 of her answers are correct.
What is her total score? (ii) One of her friends gets only 5 answers
correct. What will be her score?

SOLUTION
(i) Marks given for one correct answer = 4

So, marks given for 9 correct answers = 4 × 9 = 36
Marks given for one incorrect answer = – 2

So, marks given for 6 (= 15 – 9) incorrect answers = (–2) × 6 = –12
Therefore, Gurpreet’s total score = 36 + ( –12) = 24
(ii) Marks given for one correct answer = 4

So, marks given for 5 correct answers = 4 × 5 = 20
Marks given for one incorrect answer = (–2)

So, marks given for 10 (=15 – 5) incorrect answers = (–2) × 10 = –20
Therefore, her friend’s total score = 20 + ( –20) = 0

EXAMPLE 5 Suppose we represent the distance above the ground by a positive integer
and that below the ground by a negative integer, then answer the following:

(i) An elevator descends into a mine shaft at the rate of 5 metre per minute. What will
be its position after one hour?

(ii) If it begins to descend from 15 m above the ground, what will be its position after 45
minutes?
SOLUTION
(i) Since the elevator is going down, so the distance covered by it will be represented
by a negative integer.

Change in position of the elevator in one minute = – 5 m
Position of the elevator after 60 minutes = (–5) × 60 = – 300 m, i.e., 300 m below
ground level.
(ii) Change in position of the elevator in 45 minutes = (–5) × 45 = –225 m, i.e., 225 m
below ground level.
So, the final position of the elevator = –225 + 15 = –210 m, i.e., 210 m below
ground level.