Page 4 - LN-1

Question: What is the sum of all the 3-digit palindromes that can be created using the digits 4,
5, and 6?
A. 666 B. 2220 C. 4995 D. 4440

Explanation
C. 4995
To find the sum of all 3-digit palindromes using the digits 4, 5, and 6, follow these steps:
 Each palindrome is of the form ABA, where A and B are digits from 4, 5, and 6.
 The number A can be 4, 5, or 6, giving us three possibilities for A.
 The number B can also be 4, 5, or 6, also giving us three possibilities for B.
 This results in a total of 3 × 3 = 9 palindromes.
Let's calculate the sum:
 If A = 4, palindromes are 444, 454, 464.
 If A = 5, palindromes are 545, 555, 565.
 If A = 6, palindromes are 646, 656, 666.
Now, calculate the total sum:
 Sum for A = 4: 444 + 454 + 464 = 1362.
 Sum for A = 5: 545 + 555 + 565 = 1665.
 Sum for A = 6: 646 + 656 + 666 = 1968.
Add these results together:
 Total sum = 1362 + 1665 + 1968 = 4995.
Thus, the sum of all 3-digit palindromes is 4995.

Puzzle Time
Here’s a fun puzzle to solve:
I am a 5-digit palindrome. I am an even number. My ‘t’ digit (third digit) is half of my ‘u’ digit
(second digit). My ‘h’ digit (fourth digit) is triple my ‘t’ digit.