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Answers:

               1)










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               Area of the roads = Area of ABCD + Area of EFGH – Area of IJKL = 9900 m
               Area of the park excluding roads = Area of park – Area of the roads

               = 200100 m   2 =  200100  = 20.01 hectare
                               10000
               2) The area of margin = Area of the cardboard when margin is including – Area of
               the

               cardboard when margin is not including = 30 cm     2
               3) So, the length of cord left with Pragya = Perimeter of circular pipe – Perimeter of
               square

               = 9.12 cm
               Yes, 9.12 cm cord is left.

               4) Area of ΔQTU = PQRS area – (ΔSTU + ΔTPQ + ΔQRU) = 150 cm              2

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               5)Area of quadrilateral ABCD = Area of ΔABC + Area of ΔADC = 66 cm
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