Page 2 - WSA

Steps of construction:

1. Draw a line segment AB = 5.5 cm.

2. With A as a center and radius 5.5 cm, draw an arc.

3. With B as a center and radius 5.5 cm, draw another arc, cutting the previous arc at C.
4. Join CA and CB.

Then, ΔABC is the required equilateral triangle.

4.Solution:-

Steps of construction:

1. Draw a line segment BC = 7.5 cm.

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2. At point C, draw a ray CX to making an angle of 60 i.e. ∠XCB = 60 .
3. Along CX, set off AC = 5cm.

4. Join AB.

Then, ΔABC is the required triangle.

5. Solution:-