Page 5 - LN2

Step 5 Join PR. PQR is now obtained.

Example
0
Construct ΔΔDEF such that DE = 5 cm, DF = 3 cm and m∠EDF = 90 .
Answer:
0
To construct: ΔΔDEF where DE = 5 cm, DF = 3 cm and m∠EDF = 90 .

Steps of construction:
(a) Draw a line segment DF = 3 cm.
0
0
(b) At point D, draw an angle of 90 with the help of compass i.e., ∠XDF = 90 .
(c) Taking D as centre, draw an arc of radius 5 cm, which cuts DX at the point E.
(d) Join EF.
Therefore, DEF is the required right angled triangle DEF.