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 Method-3: Listing out the multiples

Relation between HCF and LCM:

 The product of LCM and HCF of the given natural numbers is equivalent to

the product of the given numbers.
i.e LCM × HCF of a number = Product of the Numbers

 Consider two numbers A and B, then

Therefore, LCM (A , B) × HCF (A , B) = A × B
 Ex- Show that the LCM (6, 15) × HCF (6, 15) = Product(6, 15)

Solution: LCM and HCF of 6 and 15

LCM of 6 and 15 = 30
HCF of 6 and 15 = 3

So, LCM (6, 15) × HCF (6, 15) = 30 × 3 = 90
Product of 6 and 15 = 6 × 15 = 90

Hence, LCM (6, 15) × HCF (6, 15) = Product (6, 15) = 90