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Where, L = length
B = breadth

P = perimeter

Example: A rectangular yard has length equals to 10 cm and perimeter equals to 60
cm. Find its width.
Solution: Given,
Perimeter of the yard = 60 cm
Length of the yard = 10 cm
Let W be the width of the yard.

From the formula, we know,
Perimeter, P = 2(length + width)
Substituting the values, we get;
60 = 2(10 + width)

10 + W = 30
W = 30 – 10 = 20
Hence, the width of the yard is 20cm.
Example: If the perimeter of the given rectangle is 10 cm and the length of one of its
sides is 2 cm. What will be the other side?

Solution: The perimeter of the rectangle, with one of the sides equal to 2 cm, is 10
cm.
Let the missing side be ‘a’.
We know that, the perimeter of a rectangle = 2 × (sum of adjacent sides)
10 = 2 × (2 + a) 5 = (2 + a)
a = 5 - 2 = 3 cm

Example: In the given rectangle, if a = 4 cm and d = 3 cm. Find b and c.

Solution: We know that side a = 4 cm and side d = 3 cm.