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The distance of a point from a line is the length of the perpendicular drawn from the
point to the line. Let L : Ax + By + C = 0 be a line, whose distance from the point
P (x1, y1) is d.
Thus, the perpendicular distance (d) of a line Ax + By+ C = 0 from a point (x1, y1) is given by
Example Find the distance of the point (3, – 5) from the line 3x – 4y –26 = 0.
Solution Given line is 3x – 4y –26 = 0 ... (1)
Comparing (1) with general equation of line Ax + By + C = 0, we get
A = 3, B = – 4 and C = – 26.
Given point is (x1, y1) = (3, –5). The distance of the given point from given line is