Page 2 - Lesson Note MCT 2 54
P. 2
− .
Median = + 2 ×
1
50 − 31
= 29.5 + × 10
20
190
= 29.5 +
20
= 29.5 + 9.5 = 39
Calculation of median in open end series
In case of open-end classes, the lower limit of the first-class interval and
upper limit of the last class is not given. Median is said to be the best
average in open-end class interval series.
Ex: - calculate the value of median from the following distribution.
Marks (X) No of students (F)
Below 10 3
10 – 20 13
20 – 30 18
30 – 40 11
40 and above 5
Solution: - calculation of median
Marks (X) No of students (F) Cumulative frequency
(C.F)
Below 10 3 3
10 – 20 13 16
20 – 30 18 34
30 – 40 11 45
40 and above 5 50
= ∑ = 50
Median = ℎ ℎ
2
50
= = 25th data in the series.
2
Median class is 20 - 30
= 20 f =18, c. f = 16, i = 10.
1