Page 1 - Home Assignment-Application of Heron's Formula Ch-12 (Heron's Formula)
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SAI International School
                                                     CLASS - IX

               Mathematics
               CHAPTER-12: HERON’S FORMULA


               HOME ASSIGNMENT-2




               SUBTOPIC-2: APPLICATION OF HERON’S FORMULA

               1.  Area of Parallelogram is equal to:
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                    a. base × height   b. 2(base × height)   c.  (base × height)  d.   (base + height)
                                                                 2                     2
               2.    One side of a parallelogram is 18 cm long and its area is 153        . Find the
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                     distance of the given side from its opposite side.

               3.    The diagonals of a rhombus are 15 cm and 36 cm long. Find its perimeter.

               4.  A triangle and a parallelogram have the same base and the same area. If the
                    sides of the triangle are 26 cm, 28 cm and 30 cm, and the parallelogram stands on
                    the base 28 cm, find the height of the parallelogram.
               5.  A park, in the shape of a quadrilateral ABCD, has ∠C = 90°, AB = 9m, BC = 12m,
                    CD = 5m and AD = 8 m. How much area does it occupy?
               6.  A rhombus shaped field has green grass for 18 cows to graze. If each side of the
                    rhombus is 30 m and its longer diagonal is 48 m, how much area of grass field will
                    each cow be getting?
               7.  A floral design on a floor is made up of 16 tiles which are triangular, the sides of
                    the triangle being 9 cm, 28 cm and 35 cm. Find the cost of polishing the tiles at the
                    rate of 50 paise per cm .
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               (HOME ASSIGNMENT)-2     ANSWERS
                2.
                     8.5 cm.

                3.
                     78 cm

                4.   12 cm
                5.  Area of quadrilateral ABCD = area of ∆BCD + area of ∆ABD = 30 m  + 35.5 m
                                                                                                       2
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                              2
                    = 65.5 m  (approx.)
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